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CACHE Modules on Energy in the Curriculum


Fuel Cells


Module Title: Hydrogen Adsorption and Catalyst Surface Coverage


Module Author: Jason Keith


Author Affiliation: Michigan Technological University


Course: Kinetics
and Reaction Engineering


Text Reference:
Fogler (4<sup>th edition), Section 10.2.3


Concepts: Given
the mechanism for hydrogen adsorption determine the surface coverage
on a platinum catalyst.


Problem Motivation:


Fuel cells are a promising
alternative energy conversion technology. One type of fuel cell, a proton
exchange membrane fuel cell (PEMFC) reacts hydrogen with oxygen to produce
electricity (Figure 1). Fundamental to the design of fuel cells is an
understanding of the effect of kinetics on the fuel cell performance. 


Consider the schematic
of a compressed hydrogen tank (2000 psi, regulated to 10 psi) feeding
a proton exchange membrane fuel cell, as seen in Figure 2 below. We
will now focus on the voltage / current relationship of the fuel cell.


Figure 1. Reactions in
the PEMFC


H<sub>2


H<sub>2


H<sub>2


H<sub>2


H<sub>2


O<sub>2


O<sub>2


H+


e-


e-


Anode


Electrolyte


Cathode


O<sub>2


H<sub>2</sub>O


H<sub>2</sub>O


O<sub>2


H+


H+


H+


H<sub>2


H<sub>2


H<sub>2


H<sub>2


H<sub>2</sub>O


H<sub>2</sub>O


                                                         


H<sub>2 tank


Fuel Cell


Computer


(Electric Load)


H<sub>2 out


Air in


Air / H<sub>2</sub>O out


Figure 2. Diagram for fueling a laptop.


Pressure regulator


H<sub>2 feed line


FLOW
CHANNELS 

The PEMFC reactions are: Anode:  H<sub>2                        
2H+ + 2e-


Cathode: ½
O<sub>2 + 2H+ + 2e- H<sub>2</sub>O


Overall: H<sub>2
+ ½ O<sub>2           
H<sub>2</sub>O


For each mole of
hydrogen consumed, two moles of electrons are passed through the electric
load. To convert electron flow (moles of electrons/s) to electrical
current (coulombs/s or amps), one would use Faradays constant:coulombs
/ mole of electrons. The primary objective of a fuel cell is to deliver
energy to the electric load. To calculate the energy delivery rate (also
know as power) one would multiply the current times the cell voltage: Power = Current
· Voltage. (Recall the unit conversions: and).


Background


Figure 3 shows a
polarization plot which is the relationship between current density i (fuel cell current per unit area of the electrode, in units
of milliamps per square centimeter) and cell voltage V<sub>c (in units of volts). There
are several things to note here:


Theoretical
voltage of 1.2 V


Overvoltage


Rapid drop


(kinetic losses)


Linear drop


(ohmic losses)


Rapid drop at higher currents


(mass transfer


losses)


 



The theoretical maximum
voltage of this fuel cell is 1.2 V. This is called the theoretical, or open circuit voltage .
The hydrogen
reaction rate (in moles per second, for example) is directly proportional to the current (in coulombs per second, or amperes), since for each hydrogen molecule that reacts, two electrons are
formed.
Any drop from
this maximum value is termed overvoltage. It is desired to minimize the overvolt</span><span class="Title--Char" style=" font-weight: normal;
">age so that the fuel cell can operate as efficiently as possible.
There is a
critical current density called the exchange
current density with
symbol i</span><span class="Title--Char" style=" font-weight: normal;
font-style: italic;"><sub>o. For current densities i < i</span><span class="Title--Char" style=" font-weight: normal;
font-style: italic;"><sub>o, the cell voltage is equal to the theoretical value. For current
densit</span><span class="Title--Char" style=" font-weight: normal;">ies i > i</span><span class="Title--Char" style=" font-weight: normal;
font-style: italic;"><sub>o, there is a rapid fall in cell voltage, due to a slow
reaction rate constant (kinetics). It is desired to
have as high a value of i</span><span class="Title--Char" style=" font-weight: normal;
font-style: italic;"><sub>o as possible, and as rapid kinetics as possible.
At current
densities between 100 mA/cm</span><span class="Title--Char" style=" font-weight: normal;
"><sup>2 and about 10</span><span class="Title--Char" style=" font-weight: normal;
">00 mA/cm</span><span class="Title--Char" style=" font-weight: normal;
"><sup>2, t</span><span class="Title--Char" style=" font-weight: normal;">here
is a linear fall in voltage as the current density increases. This effect
is due to the fact that there is a resistance to current and ion flow with</span><span class="Title--Char" style=" font-weight: normal;
">in the fuel cell. As the current increases, the voltage drop will
increase. In physics and electrical e</span><span class="